MYSQL 1Z0-874 Q&A - in .pdf

  • Exam Code: 1Z0-874
  • Exam Name: MySQL 5.0 Database Administrator Certified Professional Exam, Part II
  • Updated: May 30, 2026
  • Q & A: 140 Questions and Answers
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MYSQL 1Z0-874 Q&A - Testing Engine

  • Exam Code: 1Z0-874
  • Exam Name: MySQL 5.0 Database Administrator Certified Professional Exam, Part II
  • Updated: May 30, 2026
  • Q & A: 140 Questions and Answers
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MYSQL MySQL 5.0 Database Administrator Certified Professional Exam, Part II Sample Questions:

1. By default, mysqld's memory settings are...

A) Rather conservative and should be increased if possible.
B) Rather consuming and should be decreased if possible.
C) There are no default memory settings for mysqld.
D) Set to a median value good for overall general use.


2. Which of the following best describe some possible benefits of using RAID? (Choose four)

A) Read performance gains.
B) Write performance gains.
C) Better user-level security.
D) Data redundancy.
E) Better memory and processor utilization.
F) Hot-swappable disk drives.


3. Consider the following query: GRANT ALL ON world.* TO 'web'@'hostname' What privileges would this give this user?

A) ALL cannot be used when granting privileges.
B) All privileges including GRANT.
C) All privileges except GRANT.
D) SELECT, INSERT, UPDATE and DELETE.


4. Consider the following EXPLAIN of a simple Join:
mysql> EXPLAIN SELECT CountryList.Name, CityList.Name, CityList.Population
-> FROM CountryList JOIN CityList ON CountryList.Code = CityList.Country
-> WHERE CityList.Population > 8000000 *************************** 1. row *************************** id: 1 select_type: SIMPLE table: CountryList type: ALL possible_keys: NULL key: NULL key_len: NULL ref: NULL rows: 239 Extra: *************************** 2. row *************************** id: 1 select_type: SIMPLE table: CityList type: ALL possible_keys: NULL key: NULL key_len: NULL ref: NULL rows: 4079 Extra:
Using where How many rows need to be examined to perform the join?

A) 2159, the average of both numbers
B) 239, the number of rows in the first table
C) 4318, the sum of both numbers
D) 974881, the product of both numbers
E) 4079, the number of rows in the second table


5. Consider the following:
+----+-----------------+--------------+
| id | PartName | Location |
+----+-----------------+--------------+
| 1 | 40GB Hard Drive | Jacksonville |
| 2 | 1GB DDR | Atlanta |
| 3 | Keyboard | San Jose |
| 4 | Monitor | Harrisburg |
| 5 | USB Drive | Miami |
| 6 | DVD/R | Jacksonville |
+----+-----------------+--------------+
Which of the following best describes why this table should be split into a part and location table?

A) This table should not be split as it is already in third normal form.
B) Because it has multiple repeating groups in each row.
C) Because it has redundant location values.


Solutions:

Question # 1
Answer: A
Question # 2
Answer: A,B,D,F
Question # 3
Answer: C
Question # 4
Answer: D
Question # 5
Answer: C

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